14-240/Classnotes for Monday September 15

DBN: Classes: 2014-15: 14-240 / Navigation Welcome to Math 240! (additions to this web site no longer count towards good deed points) # Week of... Notes and Links 1 Sep 8 About This Class, What is this class about? (PDF, HTML), Monday, Wednesday 2 Sep 15 HW1, Monday, Wednesday, TheComplexField.pdf,HW1_solutions.pdf 3 Sep 22 HW2, Class Photo, Monday, Wednesday, HW2_solutions.pdf 4 Sep 29 HW3, Wednesday, Tutorial, HW3_solutions.pdf 5 Oct 6 HW4, Monday, Wednesday, Tutorial, HW4_solutions.pdf 6 Oct 13 No Monday class (Thanksgiving), Wednesday, Tutorial 7 Oct 20 HW5, Term Test at tutorials on Tuesday, Wednesday 8 Oct 27 HW6, Monday, Why LinAlg?, Wednesday, Tutorial 9 Nov 3 Monday is the last day to drop this class, HW7, Monday, Wednesday, Tutorial 10 Nov 10 HW8, Monday, Tutorial 11 Nov 17 Monday-Tuesday is UofT November break 12 Nov 24 HW9 13 Dec 1 Wednesday is a "makeup Monday"! End-of-Course Schedule, Tutorial F Dec 8 The Final Exam Register of Good Deeds Add your name / see who's in!

Definition:

• Subtraction: if $a,b\in F,a-b=a+(-b)$.
• Division: if $a,b\in F,a/b=a\times b^{-1}$.

Theorem:

• 8. $\forall a\in F$, $a\times 0=0$.

           *proof of 8: By F3 , $a\times 0=a\times (0+0)$
                              By F5 , $a\times (0+0)=a\times 0+a\times 0$;
                              By F3 , $a\times 0=0+a\times 0$;
                              By Thm P1,$0=a\times 0$.
       

• 9. $\nexists b\in F$ s.t. $0\times b=1$;

           $\forall b\in F$ s.t. $0\times b\neq 1$.
                   proof of 9: By F3 , $\times b=0\neq 1$.
       

• 10. $(-a)\times b=a\times (-b)=-(a\times b)$.

• 11. $(-a)\times (-b)=a\times b$.

• 12. $a\times b=0\iff a=0orb=0$.

                   proof of 12: <= : By P8 , if $a=0$ , then $a\times b=0\times b=0$;
                                     By P8 , if $b=0$ , then $a\times b=a\times 0=0$.
                                => : Assume $a\times b=0$ , if a = 0 we are done;
                                     Otherwise , by P8 , $a\neq 0$ and we have $a\times b=0=a\times 0$;  
                                                 by cancellation (P2) , $b=0$.
       

$(a+b)\times (a-b)=a^{2}-b^{2}$.

        proof: By F5 , $(a+b)\times (a-b)=a\times (a+(-b))+b\times (a+(-b))$
                                               $=a\times a+a\times (-b)+b\times a+(-b)\times b$
                                               $=a^{2}-b^{2}$

Theorem :

        $\exists !\iota :\mathbb {Z} \rightarrow F$  s.t.
              1. $\iota (0)=0,\iota (1)=1$;
              2. $\forall m,n\in \mathbb {Z} ,\iota (m+n)=\iota (m)+\iota (n)$;
              3. $\forall m,n\in \mathbb {Z} ,\iota (m\times n)=\iota (m)\times \iota (n)$.

        $\iota (2)=\iota (1+1)=\iota (1)+\iota (1)=1+1;$
        $\iota (3)=\iota (2+1)=\iota (2)+\iota (1)=\iota (2)+1;$ 

        ......                                                                          
     
        In F2 , $27---->\iota (27)=\iota (26+1)$
                                        $=\iota (26)+\iota (1)$
                                        $=\iota (26)+1$
                                        $=\iota (13\times 2)+1$
                                        $=\iota (2)\times \iota (13)+1$
                                        $=(1+1)\times \iota (13)+1$
                                        $=0\times \iota (13)+1$
                                        $=1$

http://drorbn.net/images/c/cd/MAT_240_lecture_3_%281_of_2%29.pdf (Lecture 3 notes by AM part 1 of 2) http://drorbn.net/images/6/6a/MAT240_lectuire_3_%282_of_2%29.pdf (Lecture 3 notes by AM part 2 of 2)