12-240/Classnotes for Tuesday September 18: Difference between revisions
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Proof (2): |
Proof (2): |
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Given a the field '''C''', define a map Ɩ: '''R''' → '''C''' with the properties (∀ m,n ∈ Z): |
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1) Ɩ(0) =0, Ɩ(1)=1 |
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2) Ɩ(m+n) = Ɩ(m) +Ɩ(n) |
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3) Ɩ(mn) = Ɩ(m)∙Ɩ(n) |
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BUT, also define Ɩ(x)=(x,0). Thus, it follows. ∎ |
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== Lecture 3, scanned notes upload by [[User:Starash|Starash]] == |
== Lecture 3, scanned notes upload by [[User:Starash|Starash]] == |
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Revision as of 21:50, 18 September 2012
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In this class, the professor continued with some more theorems of field and introduced definition and theorems of complex number.
Various properties of fields
Thrm 1: In a field F: 1. a+b = c+b ⇒ a=c
2. b≠0, a∙b=c∙b ⇒ a=c
3. 0 is unique.
4. 1 is unique.
5. -a is unique.
6. a^-1 is unique (a≠0)
7. -(-a)=a
8. (a^-1)^-1 =a
9. a∙0=0 **Surprisingly difficult, required distributivity.
10. ∄ 0^-1, aka, ∄ b∈F s.t 0∙b=1
11. (-a)∙(-b)=a∙b
12. a∙b=0 iff a=0 or b=0
. . .
16. (a+b)∙(a-b)= a^2 - b^2 [Define a^2 = a∙a] Hint: Use distributive law
Thrm 2: Given a field F, there exists a map Ɩ: Z → F with the properties (∀ m,n ∈ Z):
1) Ɩ(0) =0, Ɩ(1)=1
2) Ɩ(m+n) = Ɩ(m) +Ɩ(n)
3) Ɩ(mn) = Ɩ(m)∙Ɩ(n)
Furthermore, Ɩ is unique.
Rough proof:
Test somes cases:
Ɩ(2) = Ɩ(1+1) = Ɩ(1) + Ɩ(1) = 1 + 1 ≠ 2
Ɩ(3) = Ɩ(2 +1)= Ɩ(2) + Ɩ(1) = 1+ 1+ 1 ≠ 3
. . .
Ɩ(n) = 1 + ... + 1 (n times)
Ɩ(-3) = ?
Ɩ(-3 + 3) = Ɩ(-3) + Ɩ(3) ⇒ Ɩ(-3) = -Ɩ(3) = -(1+1+1)
What about uniqueness? Simply put, we had not choice in the definition of Ɩ. All followed from the given properties.
At this point, we will be lazy and simply denote Ɩ(3) = 3_f [3 with subscript f]
∃ m≠0, m ∈ N, Ɩ(m) =0
In which case, there is a smallest m<0, for which Ɩ(m)=0. 'm' is the characteristic of F. Denoted char(F). Examples: char(F_2)=2, char(F_3)=3... but NOTE: char(R)=0
Thrm: If F is a field and char(F) >0, then char(F) is a prime number.
Proof: Suppose char(F) =m, m>0. Suppose also m is not prime: m=ts, t,s ∈ N.
Then, Ɩ(m) = 0 = Ɩ(t)∙Ɩ(s) ⇒ Ɩ(t)=0 or Ɩ(s)=0 by P12.
If Ɩ(t)=0 ⇒ t≧m ⇒ m=t, s=1 or likewise for Ɩ(s)=0, and m=s, t=1
In any factorization of m, one of the factors is m and the other is 1. So m is prime. ∎
Complex number
Abstraction, generalization, definition, examples, properties, dream, implications, realization = formalization, PROOF.
Consider that fact that in R, ∄ x s.t. x^2 = -1
Dream: Add new number element 𝒊 to R, so as to still get a field & 𝒊^2 = -1
Implications: By adding 𝒊, we must add 7𝒊, and 2+7𝒊, 3+4𝒊, (2+7𝒊)∙(3+4𝒊), (2+7𝒊)^-1, etc.
So, how do we define this field?
Definition
C = {(a,b): a,b ∈ R} Also, 0 (of the field) = (0,0); 1( of the field) = (1,0)
Define addition: (a,b)+(c,d) = (a+c, b+d)
Define multification: (a,b)(c,d) = (ad-bd, ad+bc)
Theorems:
Thrm. 1. (C, 0, 1, +, ∙) is a field.
Thrm. 2. ∃ 𝒊 ∈ C s.t. 𝒊^2 = -1
Thrm. 3. C contains R
Proof (1): Show that each of the field axioms holds for C.
Ex. F1(a): ƶ1 + ƶ2 = ƶ2 + ƶ1, where ƶ1 = (a1, b1) and ƶ2 = (a2, b2)
LHS: (a1,b1)+(a2,b2) = (a1+a2, b1+b2)
RHS: (a2,b2)+(a1,b1) = (a2+a1, b2+b1)
LHS=RHS by F1 of R
F1(b) and so on...
Proof (2): Given a the field C, define a map Ɩ: R → C with the properties (∀ m,n ∈ Z):
1) Ɩ(0) =0, Ɩ(1)=1
2) Ɩ(m+n) = Ɩ(m) +Ɩ(n)
3) Ɩ(mn) = Ɩ(m)∙Ɩ(n)
BUT, also define Ɩ(x)=(x,0). Thus, it follows. ∎
Lecture 3, scanned notes upload by Starash
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