14-240/Tutorial-Sep30

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Boris

Problem

Find a set [math]\displaystyle{ S }[/math] of two elements that satisfies the following:

  • [math]\displaystyle{ S }[/math] satisfies all the properties of the field except distributivity.
  • [math]\displaystyle{ \exists x \in S, 0x \neq 0 }[/math].

Solution:

Let [math]\displaystyle{ a \in S }[/math] be the additive identity and [math]\displaystyle{ b \in S }[/math] be the multiplicative identity where [math]\displaystyle{ a \neq b }[/math]. After trial and error, we have the following addition and multiplication tables:

[math]\displaystyle{ + }[/math] [math]\displaystyle{ a }[/math] [math]\displaystyle{ b }[/math]
[math]\displaystyle{ a }[/math] [math]\displaystyle{ b }[/math] [math]\displaystyle{ b }[/math]
[math]\displaystyle{ b }[/math] [math]\displaystyle{ b }[/math] [math]\displaystyle{ a }[/math]
[math]\displaystyle{ \times }[/math] [math]\displaystyle{ a }[/math] [math]\displaystyle{ b }[/math]
[math]\displaystyle{ a }[/math] [math]\displaystyle{ a }[/math] [math]\displaystyle{ b }[/math]
[math]\displaystyle{ b }[/math] [math]\displaystyle{ a }[/math] [math]\displaystyle{ b }[/math]

Nikita