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{{14-240/Navigation}} |
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{{14-240/Navigation}} |
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Definition: |
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==Definition of Subtraction and Division== |
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* Subtraction: if <math>a, b \in F, a - b = a + (-b)</math>. |
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* Subtraction: if <math>a, b \in F, a - b = a + (-b)</math>. |
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* Division: if <math>a, b \in F, a / b = a \times b^{-1}</math>. |
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* Division: if <math>a, b \in F, a / b = a \times b^{-1}</math>. |
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==Basic Properties of a Field (cont'd)== |
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* 8. <math>\forall a \in F</math>, <math>a \times 0 = 0</math>.
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'''8.''' <math>\forall a \in F</math>, <math>a \times 0 = 0</math>. |
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;Proof of 8 |
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*proof of 8: By F3 , <math> a \times 0 = a \ times (0 + 0)</math> |
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By F5 , <math>a \times (0 + 0) = a \times 0 + a \times 0</math>;
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:By F3 , <math>a \times 0 = a \times (0 + 0)</math> |
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By F3 , <math>a \times 0 = 0 + a \times 0</math>;
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:By F5 , <math>a \times (0 + 0) = a \times 0 + a \times 0</math>; |
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By Thm P1,<math>0 = a \times 0</math>.
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:By F3 , <math>a \times 0 = 0 + a \times 0</math>; |
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:By Thm P1, <math>0 = a \times 0</math>. |
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* 9. <math>\nexists b \in F</math> s.t. <math>0 \times b = 1</math>;
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'''9.''' <math>\nexists b \in F</math> s.t. <math>0 \times b = 1</math>; |
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<math>\forall b \in F</math> s.t. <math>0 \times b \neq 1</math>.
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:<math>\forall b \in F</math> s.t. <math>0 \times b \neq 1</math>. |
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;Proof of 9 |
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proof of 9: By F3 , <math>\times b = 0 \neq 1</math>. |
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:By F3 , <math>\times b = 0 \ neq 1</math> . |
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* 10. <math>(-a) \times b = a \times (-b) = -(a \times b)</math>.
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'''10.''' <math>(-a) \times b = a \times (-b) = -(a \times b)</math>. |
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* 11. <math>(-a) \times (-b) = a \times b</math>.
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'''11.''' <math>(-a) \times (-b) = a \times b</math>. |
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* 12. <math>a \times b = 0 \iff a = 0 or b = 0</math>.
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'''12.''' <math>a \times b = 0 \iff a = 0</math> or <math>b = 0</math>. |
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;Proof of 12 |
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proof of 12: <= : By P8 , if <math>a = 0</math> , then <math>a \times b = 0 \times b = 0</math>; |
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:'''<= :''' |
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By P8 , if <math>b = 0</math> , then <math>a \times b = a \times 0 = 0</math>. |
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=> : Assume <math>a \times b = 0 </math> , if a = 0 we are done; |
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:By P8 , if <math>a = 0</math> , then <math>a \times b = 0 \times b = 0</math>; |
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Otherwise , by P8 , <math>a \neq 0 </math> and we have <math>a \times b = 0 = a \times 0</math>; |
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:By P8 , if <math>b = 0</math> , then <math>a \times b = a \times 0 = 0</math>. |
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:'''=> :''' Assume <math>a \times b = 0 </math> , if a = 0 we are done; |
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by cancellation (P2) , <math>b = 0</math>. |
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: Otherwise , by P8 , <math>a \neq 0 </math> and we have <math>a \times b = 0 = a \times 0</math>; |
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:by cancellation (P2) , <math>b = 0</math>. |
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<math>(a + b) \times (a - b) = a^2 - b^2</math>. |
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<math>(a + b) \times (a - b) = a^2 - b^2</math>. |
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;Proof |
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proof: By F5 , <math>(a + b) \times (a - b) = a \times (a + (-b)) + b \times (a + (-b))</math> |
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<math>= a \times a + a \times (-b) + b \times a + (-b) \times b</math> |
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:By F5 , <math>(a + b) \times (a - b) = a \times (a + (-b)) + b \times (a + (-b))</math> |
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<math>= a^2 - b^2</math>
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:<math>= a^2 - b^2</math> |
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Theorem : |
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<math>\exists! \iota : \Z \rightarrow F</math> s.t. |
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1. <math>\iota(0) = 0 , \iota(1) = 1</math>; |
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2. <math>\forall m ,n \in \Z, \iota(m+n) = \iota(m) + \iota(n)</math>; |
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3. <math>\forall m ,n \in \Z, \iota(m\times n) = \iota(m) \times \iota(n)</math>. |
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<math>\iota(2) = \iota(1+1) = \iota(1) + \iota(1) = 1 + 1;</math> |
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<math>\iota(3) = \iota(2+1) = \iota(2) + \iota(1) = \iota(2) + 1;</math>
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<math>\exists! \iota : \Z \rightarrow F</math> s.t. |
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:1. <math>\iota(0) = 0 , \iota(1) = 1</math>; |
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:2. <math>\forall m ,n \in \Z, \iota(m+n) = \iota(m) + \iota(n)</math>; |
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:3. <math>\forall m ,n \in \Z, \iota(m\times n) = \iota(m) \times \iota(n)</math>. |
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;Examples |
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...... |
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<math>\iota(2) = \iota(1+1) = \iota(1) + \iota(1) = 1 + 1;</math> |
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<math>\iota(3) = \iota(2+1) = \iota(2) + \iota(1) = \iota(2) + 1;</math> |
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In F2: |
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In F2 , <math>27 ----> \iota(27) = \iota(26 + 1) </math> |
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<math> |
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<math>= \iota(26) + \iota(1)</math> |
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\begin{align} |
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<math>= \iota(26) + 1</math> |
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27 ----> \iota(27) &= \iota(26 + 1) \\ |
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<math>= \iota(13 \times 2) + 1</math> |
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<math>= \iota(2) \times \iota(13) + 1</math>
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&= \iota(26) + \iota(1)\\ |
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&= \iota(26) + 1\\ |
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<math>= (1 + 1) \times \iota(13) + 1</math> |
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&= \iota(13 \times 2) + 1\\ |
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<math>= 0 \times \iota(13) + 1</math> |
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&= \iota(2) \times \iota(13) + 1\\ |
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<math>= 1</math> |
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&= (1 + 1) \times \iota(13) + 1\\ |
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http://drorbn.net/images/c/cd/MAT_240_lecture_3_%281_of_2%29.pdf (Lecture 3 notes by AM part 1 of 2) |
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&= 0 \times \iota(13) + 1\\ |
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http://drorbn.net/images/6/6a/MAT240_lectuire_3_%282_of_2%29.pdf (Lecture 3 notes by AM part 2 of 2) |
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&= 1 |
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\end{align} |
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</math> |
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==Scanned Lecture Notes by [[User:AM|AM]]== |
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<gallery> |
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File:MAT 240 lecture 3 (1 of 2).pdf|page 1 |
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File:MAT240 lectuire 3 (2 of 2).pdf|page 2 |
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</gallery> |
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==Scanned Lecture Notes by [[User Boyang.wu|Boyang.wu]]== |
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[[File:W21.pdf]] |
Welcome to Math 240! (additions to this web site no longer count towards good deed points)
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#
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Week of...
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Notes and Links
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1
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Sep 8
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About This Class, What is this class about? (PDF, HTML), Monday, Wednesday
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2
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Sep 15
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HW1, Monday, Wednesday, TheComplexField.pdf,HW1_solutions.pdf
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3
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Sep 22
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HW2, Class Photo, Monday, Wednesday, HW2_solutions.pdf
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4
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Sep 29
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HW3, Wednesday, Tutorial, HW3_solutions.pdf
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5
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Oct 6
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HW4, Monday, Wednesday, Tutorial, HW4_solutions.pdf
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6
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Oct 13
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No Monday class (Thanksgiving), Wednesday, Tutorial
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7
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Oct 20
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HW5, Term Test at tutorials on Tuesday, Wednesday
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8
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Oct 27
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HW6, Monday, Why LinAlg?, Wednesday, Tutorial
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9
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Nov 3
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Monday is the last day to drop this class, HW7, Monday, Wednesday, Tutorial
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10
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Nov 10
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HW8, Monday, Tutorial
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11
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Nov 17
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Monday-Tuesday is UofT November break
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12
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Nov 24
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HW9
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13
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Dec 1
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Wednesday is a "makeup Monday"! End-of-Course Schedule, Tutorial
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F
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Dec 8
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The Final Exam
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Register of Good Deeds
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Add your name / see who's in!
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Definition of Subtraction and Division
- Subtraction: if .
- Division: if .
Basic Properties of a Field (cont'd)
8. , .
- Proof of 8
- By F3 ,
- By F5 , ;
- By F3 , ;
- By Thm P1, .
9. s.t. ;
- s.t. .
- Proof of 9
- By F3 , .
10. .
11. .
12. or .
- Proof of 12
- <= :
- By P8 , if , then ;
- By P8 , if , then .
- => : Assume , if a = 0 we are done;
- Otherwise , by P8 , and we have ;
- by cancellation (P2) , .
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- Proof
- By F5 ,
Theorem
s.t.
- 1. ;
- 2. ;
- 3. .
- Examples
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In F2:
Scanned Lecture Notes by AM
Scanned Lecture Notes by Boyang.wu
File:W21.pdf