12-267/Homework Assignment 7: Difference between revisions
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This assignment is due in class on Tuesday November 20. Here and everywhere, '''neatness counts!!''' You may be brilliant and you may mean just the right things, but if your readers have a hard time deciphering your work they will give up and assume it is wrong. |
This assignment is due in class on Tuesday November 20. Here and everywhere, '''neatness counts!!''' You may be brilliant and you may mean just the right things, but if your readers have a hard time deciphering your work they will give up and assume it is wrong. |
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'''Task 4.''' In view of the theorem about convergence of power series solutions (Fuchs' theorem), give a lower bound on the radius of convergence of the series solution of the equation <math>(x^2-2x-3)y''+xy'+4y=0</math> near <math>x=0</math>. |
'''Task 4.''' In view of the theorem about convergence of power series solutions (Fuchs' theorem), give a lower bound on the radius of convergence of the series solution of the equation <math>(x^2-2x-3)y''+xy'+4y=0</math> near <math>x=0</math>. |
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'''Task 5.''' |
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# Find a recurrence relation satisfied by <math>a_n:=\begin{pmatrix}2n\\n\end{pmatrix}</math>. |
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# Find a differential equation satisfied by <math>y(x):=\sum_{n=0}^\infty\begin{pmatrix}2n\\n\end{pmatrix}x^n</math>. |
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# Solve that equation to determine <math>y(x)</math> in general, and <math>\sum_{n=0}^\infty\frac{1}{5^n}\begin{pmatrix}2n\\n\end{pmatrix}</math> in particular. |
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Revision as of 18:41, 14 November 2012
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This assignment is due in class on Tuesday November 20. Here and everywhere, neatness counts!! You may be brilliant and you may mean just the right things, but if your readers have a hard time deciphering your work they will give up and assume it is wrong.
Task 1. Find the radius of convergence of the series
- [math]\displaystyle{ \sum_{n=0}^\infty 2^nx^n }[/math].
- [math]\displaystyle{ \sum_{n=0}^\infty\frac{n}{2^n}x^n }[/math].
- [math]\displaystyle{ \sum_{n=0}^\infty\frac{(2x+1)^n}{n^2} }[/math] near [math]\displaystyle{ x=-\frac12 }[/math].
Task 2. Solve the equation [math]\displaystyle{ (y')^2=1-y^2 }[/math]; [math]\displaystyle{ y(0)=1 }[/math] using power series up to and including the coefficient of [math]\displaystyle{ x^5 }[/math]. Then compare your result with the Taylor expansion of the exact solution.
Task 3. Find the recurrence relation defining the power series solutions of the following equations:
- [math]\displaystyle{ y''-xy'-y=0 }[/math] with [math]\displaystyle{ y(0)=1 }[/math] and [math]\displaystyle{ y'(0)=0 }[/math].
- [math]\displaystyle{ y''-xy'-y=0 }[/math] with [math]\displaystyle{ y(1)=1 }[/math] and [math]\displaystyle{ y'(1)=0 }[/math].
- [math]\displaystyle{ (1-x)y''+y=0 }[/math] with [math]\displaystyle{ y(0)=0 }[/math] and [math]\displaystyle{ y'(0)=1 }[/math].
Task 4. In view of the theorem about convergence of power series solutions (Fuchs' theorem), give a lower bound on the radius of convergence of the series solution of the equation [math]\displaystyle{ (x^2-2x-3)y''+xy'+4y=0 }[/math] near [math]\displaystyle{ x=0 }[/math].
Task 5.
- Find a recurrence relation satisfied by [math]\displaystyle{ a_n:=\begin{pmatrix}2n\\n\end{pmatrix} }[/math].
- Find a differential equation satisfied by [math]\displaystyle{ y(x):=\sum_{n=0}^\infty\begin{pmatrix}2n\\n\end{pmatrix}x^n }[/math].
- Solve that equation to determine [math]\displaystyle{ y(x) }[/math] in general, and [math]\displaystyle{ \sum_{n=0}^\infty\frac{1}{5^n}\begin{pmatrix}2n\\n\end{pmatrix} }[/math] in particular.