12-267/Homework Assignment 6: Difference between revisions

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near the point <math>(x,y)=(1,2)</math>.
near the point <math>(x,y)=(1,2)</math>.


'''Task 3.''' Solve using diagonalization (one solution is enough):
'''Task 3.''' (Not for grade). Find a quadratic differential equation whose phase portrait is as below.
# <math>v'=\begin{pmatrix} 2 & -1 \\ 3 & -2 \end{pmatrix}v + \begin{pmatrix} e^t \\ t \end{pmatrix}</math>.
# <math>v'=\begin{pmatrix} 2 & -5 \\ 1 & -2 \end{pmatrix}v + \begin{pmatrix} -\cos t \\ \sin t \end{pmatrix}</math>.

'''Task 5.''' (Not for grade). Find a quadratic differential equation whose phase portrait is as below.


[[Image:12-267-MonkeySaddleFlow.png|center|400px]]
[[Image:12-267-MonkeySaddleFlow.png|center|400px]]

Revision as of 21:25, 2 November 2012

In Preparation

The information below is preliminary and cannot be trusted! (v)

This assignment is due in class on Friday November 9. Here and everywhere, neatness counts!! You may be brilliant and you may mean just the right things, but if your readers have a hard time deciphering your work they will give up and assume it is wrong.

Task 1. Draw the phase portraits for the following systems, near :

  1. .
  2. .
  3. .
  4. .
  5. .

Task 2. Draw the phase portrait of the system

near the point .

Task 3. Solve using diagonalization (one solution is enough):

  1. .
  2. .

Task 5. (Not for grade). Find a quadratic differential equation whose phase portrait is as below.

12-267-MonkeySaddleFlow.png

Hint. "Monkey Saddle".