Additions to the MAT 1100 web site no longer count towards good deed points
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Week of...
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Notes and Links
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1
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Sep 13
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About This Class, Tuesday - Non Commutative Gaussian Elimination, Thursday
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2
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Sep 20
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Tuesday - Homomorphisms and Normal Groups, Thursday - Isomorphism Theorems
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3
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Sep 27
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Class Photo, HW1, HW1 solution
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4
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Oct 4
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5
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Oct 11
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HW2, HW2 solution
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6
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Oct 18
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7
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Oct 25
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Term Test
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8
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Nov 1
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HW3, HW3 solution
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9
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Nov 8
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Monday-Tuesday is Fall Break, One Theorem, Two Corollaries, Four Weeks
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10
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Nov 15
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HW4, HW4 solution
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11
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Nov 22
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12
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Nov 29
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HW5, HW5 solution
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13
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Dec 6
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Boxing Day Handout, see also December 2010 Schedule. Some Class Notes
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F
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Dec 13
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Final exam, Tuesday December 14 10-1, Bahen 6183
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Register of Good Deeds
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 Add your name / see who's in!
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 See Non Commutative Gaussian Elimination
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This assignment is due by the end of my office hours (at 12:30) on Thursday December 9, 2010.
Solve the following questions
Problem 1. Let
be a module over a PID
. Assume that
is isomorphic to
, with
non-zero non-units and with
. Assume also that
is isomorphic to
, with
non-zero non-units and with
. Prove that
, that
, and that
for each
.
Problem 2. Let
and
be primes in a PID
such that
, let
denote the operation of "multiplication by
", acting on any
-module
, and let
and
be positive integers.
- For each of the
-modules
,
, and
, determine
and
.
- Explain why this approach for proving the uniqueness in the structure theorem for finitely generated modules fails.
Problem 3. (comprehensive exam, 2009) Find the tensor product of the
modules
("Laurent polynomials in
") and
(here
acts on
as
).
Problem 4. (from Selick) Show that if
is a PID and
is a multiplicative subset of
then
is also a PID.
Definition. The "rank" of a module
over a (commutative) domain
is the maximal number of
-linearly-independent elements of
. (Linear dependence and independence is defined as in vector spaces).
Definition. An element
of a module
over a commutative domain
is called a "torsion element" if there is a non-zero
such that
. Let
denote the set of all torsion elements of
. (Check that
is always a submodule of
, but don't bother writing this up). A module
is called a "torsion module" if
.
Problem 5. (Dummit and Foote, page 468) Let
be a module over a commutative domain
.
- Suppose that
has rank
and that
is a maximal set of linearly independent elements of
. Show that
is isomorphic to
and that
is a torsion module.
- Converesely show that if
contains a submodule
which is isomorphic to
for some
, and so that
is torsion, then the rank of
is
.
Problem 6. (see also Dummit and Foote, page 469) Show that the ideal
in
, regarded as a module over
, is finitely generated but cannot be written in the form
.