14-240/Tutorial-Sep30: Difference between revisions

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We verify that <math>S</math> satisfies (1) and (2). By the addition and multiplication tables, <math>S</math> is closed under addition and scalar multiplication. Since <math>a + b = b + a = b</math> and <math>ab = ba = a</math>, then <math>S</math> is commutative.
We verify that <math>S</math> satisfies (1) and (2). By the addition and multiplication tables, <math>S</math> is closed under addition and scalar multiplication. Since <math>a + b = b + a = b</math> and <math>ab = ba = a</math>, then <math>S</math> is commutative. By extension, <math>S</math> is also associative.


==Nikita==
==Nikita==

Revision as of 23:09, 4 October 2014

Boris

Problem

Find a set of two elements that satisfies the following:

(1) satisfies all the properties of the field except distributivity.

(2) .

Solution:

Let where is the additive identity and is the multiplicative identity and . After trial and error, we have the following addition and multiplication tables:

We verify that satisfies (1) and (2). By the addition and multiplication tables, is closed under addition and scalar multiplication. Since and , then is commutative. By extension, is also associative.

Nikita