14-240/Tutorial-November4: Difference between revisions

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Let <math>K = \{1, x, x^2, ..., x^{n - 1}, x^n\}</math> be the standard ordered basis of <math>P_n</math>. Define a relation <math>T: P_{n}(R) \to R</math> by <math>T(f(x)) = f(a)</math>.
Let <math>K = \{1, x, x^2, ..., x^{n - 1}, x^n\}</math> be the standard ordered basis of <math>P_n</math> and <math>f(x) \in P_{n}(R)</math>. Then <math>f(x) = \displaystyle\sum_{i=1}^{n} c_ig_i(x)</math> where <math>c_i \in R</math> and <math>g_i(x) \in K</math>. Define <math>T: P_{n}(R) \to R</math> by <math>T(\displaystyle\sum_{i=1}^{n} c_ig_i(x))= \displaystyle\sum_{i=1}^{n} c_ig_i(a)</math>. Then it is easy to show that <math>T</math> is both well-defined and linear. Afterwards, show that <math>rank(T) = 1</math> and use the rank-nullity theorem to conclude that <math>dim(W) = n</math>.





Revision as of 18:10, 29 November 2014

Boris

Question 26 on Page 57 in Homework 5

Let and be a subspace of . Find .


First, let . Then we can decompose since there is a such that . From here, there are several approaches:


Approach 1: Use Isomorphisms


We show that is isomorphic to . Let be the standard ordered basis of and be a subset of . Then there is a unique linear transformation such that where . Show that is one-to-one and onto and conclude that .


Approach 2: Use the Rank-Nullity Theorem


Let be the standard ordered basis of and . Then where and . Define by . Then it is easy to show that is both well-defined and linear. Afterwards, show that and use the rank-nullity theorem to conclude that .


Approach 3: Find a Basis with the Decomposed Polynomial

Approach 4: Find a Basis without the Decomposed Polynomial