07-1352/Class Notes for January 23: Difference between revisions

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x}{4725}-\frac{t_2^7 x}{4725}+\frac{1}{675} t_1 t_2^6 x-\frac{1}{225} t_1^2 t_2^5 x+\frac{1}{135} t_1^3 t_2^4 x-\frac{1}{135}
x}{4725}-\frac{t_2^7 x}{4725}+\frac{1}{675} t_1 t_2^6 x-\frac{1}{225} t_1^2 t_2^5 x+\frac{1}{135} t_1^3 t_2^4 x-\frac{1}{135}
t_1^4 t_2^3 x+\frac{1}{225} t_1^5 t_2^2 x-\frac{1}{675} t_1^6 t_2 x</math>
t_1^4 t_2^3 x+\frac{1}{225} t_1^5 t_2^2 x-\frac{1}{675} t_1^6 t_2 x</math>
:<math>-\frac{1}{11} t_1 x^9+\frac{t_2
x^9}{11}+\frac{2414 t_1^3 x^7}{51975}-\frac{2414 t_2^3 x^7}{51975}+\frac{53243 t_1 t_2^2
x^7}{467775}-\frac{53243 t_1^2 t_2 x^7}{467775}</math>
::<math>-\frac{4058 t_1^5 x^5}{467775}+\frac{4058 t_2^5
x^5}{467775}-\frac{3904 t_1 t_2^4 x^5}{93555}+\frac{782 t_1^2 t_2^3 x^5}{10395}-\frac{782 t_1^3 t_2^2
x^5}{10395}+\frac{3904 t_1^4 t_2 x^5}{93555}</math>
::<math>+\frac{331 t_1^7 x^3}{467775}-\frac{331 t_2^7
x^3}{467775}+\frac{331 t_1 t_2^6 x^3}{66825}-\frac{331 t_1^2 t_2^5 x^3}{22275}+\frac{331 t_1^3 t_2^4
x^3}{13365}-\frac{331 t_1^4 t_2^3 x^3}{13365}+\frac{331 t_1^5 t_2^2 x^3}{22275}-\frac{331 t_1^6 t_2
x^3}{66825}</math>
::<math>-\frac{2 t_1^9 x}{93555}+\frac{2 t_2^9 x}{93555}-\frac{2 t_1 t_2^8 x}{10395}+\frac{8 t_1^2
t_2^7 x}{10395}-\frac{8 t_1^3 t_2^6 x}{4455}+\frac{4 t_1^4 t_2^5 x}{1485}-\frac{4 t_1^5 t_2^4
x}{1485}+\frac{8 t_1^6 t_2^3 x}{4455}-\frac{8 t_1^7 t_2^2 x}{10395}+\frac{2 t_1^8 t_2
x}{10395}</math>


and
and
Line 31: Line 45:
:<math>-\frac{1147 t_1^2 x^6}{14175}+\frac{1147 t_1 t_2
:<math>-\frac{1147 t_1^2 x^6}{14175}+\frac{1147 t_1 t_2
x^6}{14175}+\frac{13}{525} t_1^4 x^4+\frac{878 t_1^2 t_2^2 x^4}{14175}-\frac{1229 t_1^3 t_2 x^4}{14175}-\frac{1}{525} t_1^6
x^6}{14175}+\frac{13}{525} t_1^4 x^4+\frac{878 t_1^2 t_2^2 x^4}{14175}-\frac{1229 t_1^3 t_2 x^4}{14175}-\frac{1}{525} t_1^6
x^2+\frac{2}{105} t_1^3 t_2^3 x^2-\frac{1}{35} t_1^4 t_2^2 x^2+\frac{2}{175} t_1^5 t_2 x^2</math>?
x^2+\frac{2}{105} t_1^3 t_2^3 x^2-\frac{1}{35} t_1^4 t_2^2 x^2+\frac{2}{175} t_1^5 t_2 x^2</math>
:<math>-\frac{2939 t_1^2
x^8}{42525}+\frac{2939 t_1 t_2 x^8}{42525}+\frac{1327 t_1^4 x^6}{42525}+\frac{2896 t_1^2 t_2^2
x^6}{42525}-\frac{4223 t_1^3 t_2 x^6}{42525}</math>
::<math>-\frac{199 t_1^6 x^4}{42525}+\frac{20}{567} t_1^3 t_2^3
x^4-\frac{97 t_1^4 t_2^2 x^4}{1701}+\frac{1124 t_1^5 t_2 x^4}{42525}+\frac{2 t_1^8
x^2}{8505}+\frac{2}{243} t_1^4 t_2^4 x^2-\frac{16 t_1^5 t_2^3 x^2}{1215}+\frac{8 t_1^6 t_2^2
x^2}{1215}-\frac{16 t_1^7 t_2 x^2}{8505}</math>?


==A HOMFLY Braidor==
==A HOMFLY Braidor==

Revision as of 22:02, 23 January 2007

A Second Look

We'll take a second look at 06-1350/Class Notes for Tuesday October 24.

A Numerology Problem

Question. Can you find nice formulas for the functions and of the variables , and , whose Taylor expansions are

and

?

A HOMFLY Braidor

The Algebra

Let be the free associative (but non-commutative) algebra generated by the elements of the symmetric group on and by formal variables and , and let be the quotient of by the following "HOMFLY" relations:

  1. commutes with everything else.
  2. The product of permutations is as in the symmetric group .
  3. If is a permutation then .
  4. , where is the transposition of and .

Finally, declare that while for every and every , and let be the graded completion of .

We say that an element of is "sorted" if it is written in the form where is a permutation and and the 's are all non-negative integer. The HOMFLY relations imply that every element of is a linear combinations of sorted elements. Thus as a vector space, can be identified with the ring of power series in the variables tensored with the group ring of . The product of is of course very different than that of .

Examples.

  1. The general element of is where denotes the identity permutation and is a power series in two variables and . is commutative.
  2. The general element of is where and are power series in three variables and and are the two elements of . is not commutative and its product is non-trivial to describe.
  3. The general element of is described using power series in 4 variables. The general element of is described using n! power series in variables.

The algebra embeds in in a trivial way by regarding as a subset of in the obvious manner; thus when given an element of we are free to think of it also as an element of . There is also a non-trivial map defined as follows:

  1. .
  2. .
  3. acts on permutations by "shifting them one unit to the right", i.e., by identifying with .

The Equations

We seek to find a "braidor"; an element of satisfying:

  • (higher order terms).
  • in .

With the vector space identification of with in mind, we are seeking two power series of three variables each, whose low order behaviour is specified and which are required to satisfy 6 functional equations written in terms of 4 variables.

The Equations in Functional Form

A Solution

The first few terms of a solution can be computed using a computer, as shown above and below. But a true solution, written in a functional form, is still missing.

Computer Games

A primitive mathematica program to play with these objects is here.