Notes for AKT-170110-1/0:43:57

Kauffman often defines his bracket using the variable $A$, it is not invariant under Reidemeister 1, a positive curl spits out $-A^{3}$. Multiplying through the relation for the $\pm$ crossing by $-A^{\mp 3}$ and absorbing that factor into the crossing, we get Dror's Kauffman bracket with $q=-A^{-2}$. Roland