Notes for AKT-170110-1/0:43:57
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Kauffman often defines his bracket using the variable A, it is not invariant under Reidemeister 1, a positive curl spits out [math]\displaystyle{ -A^3 }[/math]. Multiplying through the relation for the [math]\displaystyle{ \pm }[/math] crossing by [math]\displaystyle{ -A^{\mp 3} }[/math] and setting [math]\displaystyle{ q = -A^{-2} }[/math] one gets Dror's Kauffman bracket.
