Notes for AKT-090924-1/0:35:01
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Analog for [math]\displaystyle{ \mathcal{A} }[/math]: [math]\displaystyle{ \mathcal{A}(\bigcirc) }[/math] is isomorphic to [math]\displaystyle{ \mathcal{A}(|) }[/math].
(Checking the map of 'breaking the circle' is independent of the choice of breaking point is interesting.)
