Notes for AKT-090924-1/0:35:01: Difference between revisions
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<math>A(O)</math> is isomorphic to <math>A(|)</math> |
<math>A(O)</math> is isomorphic to <math>A(|)</math> |
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(Checking the map of 'breaking the circle' is independent of the choice of breaking point is interesting) |
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Revision as of 00:52, 25 September 2009
Analog for [math]\displaystyle{ A }[/math]:
[math]\displaystyle{ A(O) }[/math] is isomorphic to [math]\displaystyle{ A(|) }[/math]
(Checking the map of 'breaking the circle' is independent of the choice of breaking point is interesting)
