Notes for AKT-140108/0:08:12: Difference between revisions

From Drorbn
Jump to navigationJump to search
No edit summary
No edit summary
Line 2: Line 2:


The factor $\frac{1}{2}$ I think is as a result of the projection of the link unto the plane making each sign appear twice.
The factor $\frac{1}{2}$ I think is as a result of the projection of the link unto the plane making each sign appear twice.

\textbf{Jordan Curve Theorem}
If $C$ is a simple closed curve in \mathbb{R}^2, then the complement R^2-J has two components: the interior and the exterior, with $C$ the boundary of each.

The Jordan curve theorem implies that two distinct components in a diagram for L intersect an even number of times. Hence we add up an even
number of $\pm$ 1’s in the computation of lk(L), which yields an even number
and hence an integral linking number.

Revision as of 11:59, 23 May 2018

18S-AKT Question: Why is this sum divisible by 2? Why the $\frac{1}{2}$?

The factor $\frac{1}{2}$ I think is as a result of the projection of the link unto the plane making each sign appear twice.

\textbf{Jordan Curve Theorem} If $C$ is a simple closed curve in \mathbb{R}^2, then the complement R^2-J has two components: the interior and the exterior, with $C$ the boundary of each.

The Jordan curve theorem implies that two distinct components in a diagram for L intersect an even number of times. Hence we add up an even number of $\pm$ 1’s in the computation of lk(L), which yields an even number and hence an integral linking number.