1617-257/TUT-R-2: Difference between revisions
(Created page with "We discussed the following on 9/22/16: (1) What are the dimensions of <math>\mathbb{R}^\infty</math> and <math>\mathbb{R}^\omega</math>? (2) Let <math>S</math> be a subset o...") |
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A student gave an for problem (2) which works fine if <math>S</math> is a closed set (it depended on the fact that <math>S' \subset S</math>). |
A student gave an for problem (2) which works fine if <math>S</math> is a closed set (it depended on the fact that <math>S' \subset S</math>). |
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Let <math>\epsilon > 0</math> be given and let <math>x'' \in S''</math> be given. |
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Here's what we would have done if we had extra time to discuss: |
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Then there is some <math>x' \in S'</math> such that <math>\|x'' - x'\| < \epsilon/2.</math> |
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There is also a point <math>x \in S</math> such that <math>\|x' - x \| < \epsilon/2.</math> |
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So <math>\|x - x''\| \leq \|x - x'\| + \|x' - x''\| < \epsilon.</math> |
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Since <math>x_n \in S'</math>, there is some <math>s \in S</math> such that <math>\|x_n - s\| < \epsilon/2</math>. |
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So <math>\|s - x\| \leq \|s - x_n \| + \|x_n - x\| < \epsilon.</math> |
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Revision as of 11:57, 30 September 2016
We discussed the following on 9/22/16:
(1) What are the dimensions of [math]\displaystyle{ \mathbb{R}^\infty }[/math] and [math]\displaystyle{ \mathbb{R}^\omega }[/math]?
(2) Let [math]\displaystyle{ S }[/math] be a subset of [math]\displaystyle{ \mathbb{R}^n }[/math]. Show that the set of limit points of [math]\displaystyle{ S }[/math], [math]\displaystyle{ S' }[/math], is closed.
A student gave an for problem (2) which works fine if [math]\displaystyle{ S }[/math] is a closed set (it depended on the fact that [math]\displaystyle{ S' \subset S }[/math]).
Let [math]\displaystyle{ \epsilon \gt 0 }[/math] be given and let [math]\displaystyle{ x'' \in S'' }[/math] be given.
Then there is some [math]\displaystyle{ x' \in S' }[/math] such that [math]\displaystyle{ \|x'' - x'\| \lt \epsilon/2. }[/math]
There is also a point [math]\displaystyle{ x \in S }[/math] such that [math]\displaystyle{ \|x' - x \| \lt \epsilon/2. }[/math]
So [math]\displaystyle{ \|x - x''\| \leq \|x - x'\| + \|x' - x''\| \lt \epsilon. }[/math]
That is, [math]\displaystyle{ x \in S'. }[/math]