12-240/Classnotes for Thursday October 4: Difference between revisions
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Claim: This set is linearly independent. |
Claim: This set is linearly independent. |
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Proof: Suppose (∑ ai*ei) = 0 ({ei} is linearly dependant.) |
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(∑ ai*ei) = 0 ⇔ a1(1, 0, ..., 0) + ... + an(0, ..., 0, 1) = 0 ⇔ (a1, 0, ... , 0) + ... + (0, ... , an) = 0 |
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⇒ a1 = a2 = ... = an = 0! |
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=== Comments === |
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1. {∅} is linearly independent. (Think about logical statements like "all elements of the empty set are purple") |
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2. {u} is linearly independent when u≠0. |
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Proof: |
Revision as of 18:40, 4 October 2012
Recap
Base - what were doing today
Linear combination (lc) - We say v is a linear combination of a set S = {u1 ... un} if v = a1u1 ... anun for scalars from a field F.
Span - span(S) is the set of all linear combination of set S
Generate - We say S generates a vector space V is span(S) = V
Introduction to Basis
Linear dependance
Definition A set S subsetof V is called linearly dependant if you can express the zero vector as a linear combination of distinct vectors from S, excluding the non-trivial linear combination where all of the scalars are 0.
Otherwise, we call S linearly independant.
Examples
1. In R^3, take S = {u1 = (1,4,7), u2 = (2,5,8), u3 = (3,6,9)}
u1 - 2u2 + u3 = 0
S is linearly dependant.
2. In R^n, take {e_i} = {0, 0, ... 1, 0, 0, 0} where 1 is in the ith position, and (ei) is a vector with n entries.
Claim: This set is linearly independent.
Proof: Suppose (∑ ai*ei) = 0 ({ei} is linearly dependant.)
(∑ ai*ei) = 0 ⇔ a1(1, 0, ..., 0) + ... + an(0, ..., 0, 1) = 0 ⇔ (a1, 0, ... , 0) + ... + (0, ... , an) = 0
⇒ a1 = a2 = ... = an = 0!
Comments
1. {∅} is linearly independent. (Think about logical statements like "all elements of the empty set are purple") 2. {u} is linearly independent when u≠0.
Proof: