Notes for AKT-090924-1/0:35:01: Difference between revisions

Latest revision as of 09:11, 15 September 2011

Analog for ${\mathcal {A}}$ : ${\mathcal {A}}(\bigcirc )$ is isomorphic to ${\mathcal {A}}(|)$ .

(Checking the map of 'breaking the circle' is independent of the choice of breaking point is interesting.)

@@ Line 1: / Line 1: @@
-Analog for <math>A</math>:
+Analog for <math>\mathcal{A}</math>: <math>\mathcal{A}(\bigcirc)</math> is isomorphic to <math>\mathcal{A}(|)</math>.
+(Checking the map of 'breaking the circle' is independent of the choice of breaking point is interesting.)
-<math>A(O)</math> is isomorphic to <math>A(|)</math>
-(Checking the map of 'breaking the circle' is independent of the choice of breaking point is interesting)