Notes for AKT-090915/0:03:24: Difference between revisions

Revision as of 05:21, 16 September 2009

Review and additions to last class, corrections:

Jones polynomial is usually normalized by diving the '<>' of an unknot (i.e. divide by an additional factor of $d$ ).
We can prove all knot $K$ has $J(K)$ being a polynomial of $A^{4}$ , hence we substitute $A=q^{1/4}$ .

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+Review and additions to last class, corrections:
-Review and additions to last class, corrections: 1. Jones polynomial is usually normalized by diving the '<>' of an unknot (i.e. divide by an additional factor of d)  2.We can prove all knot K has J(K) being a polynomial of A^4, hence we substitute A=q^{1/4}
+# Jones polynomial is usually normalized by diving the '<>' of an unknot (i.e. divide by an additional factor of <math>d</math>).
+# We can prove all knot <math>K</math> has <math>J(K)</math> being a polynomial of <math>A^4</math>, hence we substitute <math>A=q^{1/4}</math>.