Notes for AKT-140124/0:23:30: Difference between revisions
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Let <math>\Lambda</math> be a symmetric, positive definite, non-singular square matrix. Then we have the following: |
Let <math>\Lambda</math> be a symmetric, positive definite, non-singular square matrix. Then we have the following: |
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<math> |
<math> \langle x - \Lambda^{-1} y, \Lambda(x - \Lambda^{-1}y)\rangle = \langle x,\Lambda x \rangle - \langle x, y \rangle - \langle \Lambda^{-1}y, \Lambda x \rangle + \langle \Lambda^{-1}y,y \rangle </math>. |
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We have <math> |
We have <math> \langle \Lambda^{-1}y, \Lambda x \rangle = \langle x,y\rangle </math> and <math> \langle \Lambda^{-1}y,y \rangle = \langle y,\Lambda^{-1}y \rangle</math> since <math>\Lambda</math> is symmetric. |
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From the above, we see that <math>-\frac12 |
From the above, we see that <math>-\frac12 \langle x - \Lambda^{-1} y, \Lambda(x - \Lambda^{-1}y) \rangle + \frac12 \langle y,\Lambda^{-1}y \rangle = -\frac12 \langle x,\Lambda x \rangle + \langle x, y \rangle</math> |
Latest revision as of 14:03, 18 June 2018
Let be a symmetric, positive definite, non-singular square matrix. Then we have the following:
.
We have and since is symmetric.
From the above, we see that