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Some foundational exercises about crossed-modules here! |
Some foundational exercises about crossed-modules here! |
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'''Solution 1.''' In fact, by the Peiffer relation $\partial(e)f=e^{-1}fe$, any $e\in\ker\partial$ is central. |
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Revision as of 17:46, 2 May 2015
Some foundational exercises about crossed-modules here!
Solution 1. In fact, by the Peiffer relation $\partial(e)f=e^{-1}fe$, any $e\in\ker\partial$ is central.
