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Constant Coefficient Homogeneous High Order ODEs
Constant Coefficient Homogeneous High Order ODEs


Ex <math>L(y) = ay" + by' +cy = 0, a, b, c \in \mathbb{R}</math>
Ex <math>Ly = a y'' + b y' + c y = 0</math>, <math>a \in \mathbb{R}, b \in \mathbb{R}, c \in \mathbb{R}</math>


Or generally <math>L(y) = \sum_k=0^n a_k y^{(k)} = 0, a_k \in \mathbb{R}</math>
Or generally <math>Ly = \sum_k=0^n a_k y^{(k)} = 0, a_k \in \mathbb{R}</math>


<math>L:{functions on \mathbb{R} \rightarrow {functions on \mathbb{R}</math> is a linear transformation ("linear operator").
<math>L:\{f: \mathbb{R} \rightarrow \mathbb{R}\} \rightarrow \{f: \mathbb{R} \rightarrow \mathbb{R}\}</math> is a linear transformation ("linear operator").


What do we expect from <math>{y:L(y) = 0} = ker(L)</math>? We expect an n-dimensional vector space.
What do we expect from <math>\{y: Ly = 0\} = ker(L)</math>? We expect an n-dimensional vector space.


Take <math> y"+y'-6y = 0</math>, guess <math> y = c, y' = \alpha e^{\alpha x}, y" = \alpha^2e^{\alpha x}</math>
Take <math> y''+y'-6y = 0</math>, guess <math> y = c, y' = \alpha e^{\alpha x}, y'' = \alpha^2e^{\alpha x}</math>


<math> \alpha^2 e^{\alpha x} + \alpha e^{\alpha x} - 6 e^{\alpha x} = 0</math>
<math> \alpha^2 e^{\alpha x} + \alpha e^{\alpha x} - 6 e^{\alpha x} = 0</math>

Latest revision as of 14:33, 24 October 2012

Week 6, Lecture 3

Constant Coefficient Homogeneous High Order ODEs

Ex ,

Or generally

is a linear transformation ("linear operator").

What do we expect from ? We expect an n-dimensional vector space.

Take , guess

So we have as the general solution.

Say we have complex . Then what?