Notes for AKT-140228/0:48:42: Revision history

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22 August 2018

  • curprev 23:1523:15, 22 August 2018‎ Gavin.hurd talk contribs‎ 351 bytes +351‎ Created page with "Proof of the claim: $$d(gs) = (dg)s+gds \implies (dg)s = d(gs)-gds$$ So <center><math>\begin{align} D_{g^{-1} A g+g^{-1} d g} (s)\\ &=ds+(g^{-1} A g+g^{-1} d g)s\\ &= ds + g..."
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