<?xml version="1.0"?>
<feed xmlns="http://www.w3.org/2005/Atom" xml:lang="en">
	<id>https://drorbn.net/index.php?action=history&amp;feed=atom&amp;title=Notes_for_AKT-140117%2F0%3A28%3A51</id>
	<title>Notes for AKT-140117/0:28:51 - Revision history</title>
	<link rel="self" type="application/atom+xml" href="https://drorbn.net/index.php?action=history&amp;feed=atom&amp;title=Notes_for_AKT-140117%2F0%3A28%3A51"/>
	<link rel="alternate" type="text/html" href="https://drorbn.net/index.php?title=Notes_for_AKT-140117/0:28:51&amp;action=history"/>
	<updated>2026-05-09T23:56:57Z</updated>
	<subtitle>Revision history for this page on the wiki</subtitle>
	<generator>MediaWiki 1.39.6</generator>
	<entry>
		<id>https://drorbn.net/index.php?title=Notes_for_AKT-140117/0:28:51&amp;diff=16513&amp;oldid=prev</id>
		<title>Donghao.ouyang: Created page with &quot;To demonstrate how to use the Euler-Lagrange equation in classical mechanics, we solve brachistochrone problem as an example.  The problem is described in the blackboard shot,...&quot;</title>
		<link rel="alternate" type="text/html" href="https://drorbn.net/index.php?title=Notes_for_AKT-140117/0:28:51&amp;diff=16513&amp;oldid=prev"/>
		<updated>2018-05-23T17:17:20Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;quot;To demonstrate how to use the Euler-Lagrange equation in classical mechanics, we solve brachistochrone problem as an example.  The problem is described in the blackboard shot,...&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;To demonstrate how to use the Euler-Lagrange equation in classical mechanics, we solve brachistochrone problem as an example.  The problem is described in the blackboard shot, which is to find the path of a particle that minimizes the time &amp;lt;math&amp;gt;T&amp;lt;/math&amp;gt; traveled from point &amp;lt;math&amp;gt;P_1&amp;lt;/math&amp;gt; to point &amp;lt;math&amp;gt;P_2&amp;lt;/math&amp;gt; in a uniform gravitational field.  In this situation, we assume there is no friction along the path; thus the energy is conserved.  Let &amp;lt;math&amp;gt;y&amp;lt;/math&amp;gt; be the vertical coordinate.  Then, by the conservation of energy, we have&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\frac{1}{2}mv^2-\frac{1}{2}mv_i^2=\frac{1}{2}mv^2=mgy.&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Thus, we have&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;v=\sqrt{2gy}.&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Then, the time &amp;lt;math&amp;gt;T&amp;lt;/math&amp;gt; may be described as&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;T=\int_{P_1}^{P_2}\frac{ds}{v},&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
where &amp;lt;math&amp;gt;ds&amp;lt;/math&amp;gt; is the infinitesimal arclength of the path.  Then, let &amp;lt;math&amp;gt;x&amp;lt;/math&amp;gt; be the horizontal coordinate, we have &amp;lt;math&amp;gt;ds=\sqrt{dx^2+dy^2}=\sqrt{1+y&amp;#039;^2}dx.&amp;lt;/math&amp;gt;  Thus, the above equation would be&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;T=\int_{P_1}^{P_2}\sqrt{\frac{1+y&amp;#039;^2}{2gy}}dx.&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Now, let &amp;lt;math&amp;gt;L=\sqrt{\frac{1+y&amp;#039;^2}{2gy}}&amp;lt;/math&amp;gt;, we apply the Euler-Lagrange equation and obtain&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\frac{\partial L}{\partial y}=-\frac{1}{2y}\sqrt{\frac{1+y&amp;#039;^2}{2g}}=\frac{d}{dx}\left(\frac{\partial L}{\partial y&amp;#039;}\right)=\frac{1}{\sqrt{2g}}\frac{2yy&amp;#039;&amp;#039;-y&amp;#039;^4-y&amp;#039;^2}{2(y(1+y&amp;#039;^2))^{3/2}}.&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
If we rearrange the equation and integrate, we obtain the equation&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;C=\frac{1}{\sqrt{2gy\left(1+y&amp;#039;^2\right)}}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
where &amp;lt;math&amp;gt;C&amp;lt;/math&amp;gt; is some constant.  Then, we rearrange the equation and obatin&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\left(1+y&amp;#039;^2\right)y=\frac{1}{2gC^2}=k^2.&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Then, we can solve this equation with parameterization and obtain the final result&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;x\left(t\right)=\frac{k^2}{2}\left(t-\sin t\right),y\left(t\right)=\frac{k^2}{2}\left(1-\cos t\right)&amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Donghao.ouyang</name></author>
	</entry>
</feed>