Iva at 12:52, 15 September 2011

2011-09-15T12:52:15Z

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We can also express <math>\mathcal{A}_n=\mathcal{D}^0_n/b(\mathcal{D}^1_n)</math> where <math>\mathcal{D}^0_n</math> is the v.s. of chord diagrams with <math>n</math> chords, <math>\mathcal{D}^1_n</math> is the v.s. of chord diagrams with one <math>T</math> shape and <math>(n-2)</math> chords and <math>b</math> is the map that takes the <math>T</math> shape to the signed sum of its four resolutions as in the 4T relation.

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Iva at 12:52, 15 September 2011