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		<title>Trefor at 04:05, 11 January 2008</title>
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		<updated>2008-01-11T04:05:16Z</updated>

		<summary type="html">&lt;p&gt;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;{{0708-1300/Navigation}}&lt;br /&gt;
&lt;br /&gt;
==Class Notes==&lt;br /&gt;
&amp;lt;span style=&amp;quot;color: red;&amp;quot;&amp;gt;The notes below are by the students and for the students. Hopefully they are useful, but they come with no guarantee of any kind.&amp;lt;/span&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Recall from last class we are going to prove the following lemma:&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Lemma 1&amp;#039;&amp;#039;&amp;#039;&lt;br /&gt;
&lt;br /&gt;
Let &amp;lt;math&amp;gt;e:\mathbb{R}\rightarrow S^1&amp;lt;/math&amp;gt; be &amp;lt;math&amp;gt;e(x) = e^{2i\pi x}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Then every path &amp;lt;math&amp;gt;\gamma:[0,1]\rightarrow S^1&amp;lt;/math&amp;gt; with &amp;lt;math&amp;gt;\gamma(0) = 1&amp;lt;/math&amp;gt; has a unique lift &amp;lt;math&amp;gt;\tilde{\gamma}:[0,1]\rightarrow\mathbb{R}&amp;lt;/math&amp;gt; such that &lt;br /&gt;
&lt;br /&gt;
0)&amp;lt;math&amp;gt;\tilde{\gamma}(o) = 0&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
1) &amp;lt;math&amp;gt;e\circ\tilde{\gamma} = \gamma&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Definition 1&amp;#039;&amp;#039;&amp;#039;&lt;br /&gt;
&lt;br /&gt;
A covering map is a map &amp;lt;math&amp;gt;p:X\rightarrow B&amp;lt;/math&amp;gt; such that &lt;br /&gt;
&lt;br /&gt;
0) B is connected and locally connected&lt;br /&gt;
&lt;br /&gt;
1) The map &amp;lt;math&amp;gt;X\rightarrow B&amp;lt;/math&amp;gt; is locally a map &amp;lt;math&amp;gt;F\times B \rightarrow B&amp;lt;/math&amp;gt; where F the &amp;quot;fiber&amp;quot; is a discrete set&lt;br /&gt;
&lt;br /&gt;
More precisely this condition means that every point in B has a neighborhood U such that &amp;lt;math&amp;gt;p^{-1}(U)&amp;lt;/math&amp;gt; is &amp;lt;math&amp;gt;F\times U&amp;lt;/math&amp;gt; for some such F&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Note 1: As is assumed in this section of the course, our map p is continuous, our spaces have base points &amp;lt;math&amp;gt;p(x_0) = b_0&amp;lt;/math&amp;gt;. Furthermore we mean, as always, pathwise connected when we say connected. &lt;br /&gt;
&lt;br /&gt;
Note 2: Recall that connected does NOT imply locally connected. Indeed recall the Cantor Comb from a previous class. &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Examples of covering maps&amp;#039;&amp;#039;&amp;#039;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
1) &amp;lt;math&amp;gt;X = F\times B \rightarrow B&amp;lt;/math&amp;gt; is trivially a covering map&lt;br /&gt;
&lt;br /&gt;
2) The map from last class, &amp;lt;math&amp;gt;e:\mathbb{R}\rightarrow S^1&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
3)&amp;lt;math&amp;gt;S^2\rightarrow S^2 /\pm 1 \cong \mathbb{R} P^2&amp;lt;/math&amp;gt; where the identification glues antipodal points on the sphere. Here &amp;lt;math&amp;gt;F = \mathbb{Z}/2&amp;lt;/math&amp;gt;. I.e., there are two preimages of each point (the two antipodal points)&lt;br /&gt;
&lt;br /&gt;
4) Likewise, &amp;lt;math&amp;gt;S^3\rightarrow\mathbb{R}P^3&amp;lt;/math&amp;gt; etc...&lt;br /&gt;
&lt;br /&gt;
5) Consider a bunch of identical floors of &amp;quot;abstract&amp;quot; parking garages all on top of each. &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Aside 1&amp;#039;&amp;#039;&amp;#039;&lt;br /&gt;
&lt;br /&gt;
Recall SO(3) the group of orientation preserving rigid rotations of &amp;lt;math&amp;gt;\mathbb{R}^3&amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Claim:&amp;#039;&amp;#039;&amp;#039; &lt;br /&gt;
&amp;lt;math&amp;gt;SO(3)\cong\mathbb{R}P^3&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Proof:&amp;#039;&amp;#039;&amp;#039;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;SO(3) = \{v\in\mathbb{R}^3\ |\ ||v||\leq\pi\}/&amp;lt;/math&amp;gt; (if &amp;lt;math&amp;gt;||v||=\pi&amp;lt;/math&amp;gt; then &amp;lt;math&amp;gt;v\sim -v&amp;lt;/math&amp;gt;)&lt;br /&gt;
&lt;br /&gt;
This is because we know that any rotation occurs about an axis. So one can encapsulate the information of a given rotation by a vector where the orientation of the vector denotes the axis and the length of the vector denotes the amount of rotation. However, a rotation by &amp;lt;math&amp;gt;\pi&amp;lt;/math&amp;gt; degrees does not matter which direction v or -v we do this in, hence the identification. But the resulting set is precisely &amp;lt;math&amp;gt;\mathbb{R}P^3&amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
We can now generalize Lemma 1 with our new concept of covering maps opposed to just the map e (which we now know is a specific example of a covering map)&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Lemma 1 (general):&amp;#039;&amp;#039;&amp;#039;&lt;br /&gt;
&lt;br /&gt;
Let &amp;lt;math&amp;gt;p:X\rightarrow B&amp;lt;/math&amp;gt; be a covering map. Then every path &amp;lt;math&amp;gt;\gamma:[0,1]\rightarrow B&amp;lt;/math&amp;gt; with &amp;lt;math&amp;gt;\gamma(0) = b_0&amp;lt;/math&amp;gt; has a unique lift &amp;lt;math&amp;gt;\tilde{\gamma}:[0,1]\rightarrow&amp;lt;/math&amp;gt; X such that &lt;br /&gt;
&lt;br /&gt;
0) &amp;lt;math&amp;gt;\tilde{\gamma}(0) = x_0&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
1) &amp;lt;math&amp;gt;p\circ\tilde{\gamma} = \gamma&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Proof&amp;#039;&amp;#039;&amp;#039;&lt;br /&gt;
&lt;br /&gt;
Cover B with good sets &amp;lt;math&amp;gt;U_{\alpha}&amp;lt;/math&amp;gt; (where by &amp;quot;good&amp;quot; we mean the inverse images look like products)&lt;br /&gt;
&lt;br /&gt;
Now &amp;lt;math&amp;gt;\gamma([0,1])&amp;lt;/math&amp;gt; is covering by these and so [0,1] is covered by &amp;lt;math&amp;gt;\{\gamma^{-1}(U_{\alpha})\}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The Lebesgue Lemma then implies that there exists N such that [i/N, (i+1)/N] such that &amp;lt;math&amp;gt;\gamma([i/N, (i+1)/N])&amp;lt;/math&amp;gt; is in one of the &amp;lt;math&amp;gt;U_{\alpha}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The lemma then follows by an inductive argument which is essentially just bookkeeping. Very loosely it is as follows: In the interval [0,1/N] we know that gamma at 0 is &amp;lt;math&amp;gt;b_0&amp;lt;/math&amp;gt; and have to uniquely define &amp;lt;math&amp;gt;\tilde{\gamma}(0) = x_0&amp;lt;/math&amp;gt;. We thus get &amp;lt;math&amp;gt;\tilde{\gamma}&amp;lt;/math&amp;gt; in this interval recalling that for continuity we have to keep &amp;lt;math&amp;gt;\tilde{\gamma}&amp;lt;/math&amp;gt; in one &amp;quot;level&amp;quot;. We thus proceed inductively through the other subintervals of [0,1] and it remains to be checked that everything does in fact work out as we expect.&lt;/div&gt;</summary>
		<author><name>Trefor</name></author>
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