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	<updated>2026-05-01T19:34:15Z</updated>
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	<entry>
		<id>https://drorbn.net/index.php?title=06-240/Classnotes_For_Thursday_November_9&amp;diff=2719</id>
		<title>06-240/Classnotes For Thursday November 9</title>
		<link rel="alternate" type="text/html" href="https://drorbn.net/index.php?title=06-240/Classnotes_For_Thursday_November_9&amp;diff=2719"/>
		<updated>2006-11-10T04:40:07Z</updated>

		<summary type="html">&lt;p&gt;Psp: &amp;#039;Multiply a row/column by a nonzero scalar&amp;#039;&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;{{06-240/Navigation}}&lt;br /&gt;
&lt;br /&gt;
==Review of Last Class==&lt;br /&gt;
{|&lt;br /&gt;
|-&lt;br /&gt;
|&#039;&#039;&#039;Problem.&#039;&#039;&#039; Find the rank (the dimension of the image) of a linear transformation &amp;lt;math&amp;gt;T&amp;lt;/math&amp;gt; whose matrix representation is the matrix A shown on the right.&lt;br /&gt;
|&amp;lt;math&amp;gt;A=\begin{pmatrix}0&amp;amp;2&amp;amp;4&amp;amp;2&amp;amp;2\\4&amp;amp;4&amp;amp;4&amp;amp;8&amp;amp;0\\8&amp;amp;2&amp;amp;0&amp;amp;10&amp;amp;2\\6&amp;amp;3&amp;amp;2&amp;amp;9&amp;amp;1\end{pmatrix}&amp;lt;/math&amp;gt;.&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{|&lt;br /&gt;
|- valign=bottom&lt;br /&gt;
|&#039;&#039;&#039;Theorem 1.&#039;&#039;&#039; If &amp;lt;math&amp;gt;T:V\to W&amp;lt;/math&amp;gt; is a linear transformation and &amp;lt;math&amp;gt;P:V\to V&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;Q:W\to W&amp;lt;/math&amp;gt; are &#039;&#039;invertible&#039;&#039; linear transformations, then the rank of &amp;lt;math&amp;gt;T&amp;lt;/math&amp;gt; is the same as the rank of &amp;lt;math&amp;gt;QTP&amp;lt;/math&amp;gt;.&lt;br /&gt;
|&amp;amp;nbsp;&amp;amp;nbsp;&amp;amp;nbsp;&lt;br /&gt;
|&#039;&#039;&#039;Proof.&#039;&#039;&#039; Owed.&lt;br /&gt;
|- valign=bottom&lt;br /&gt;
|&#039;&#039;&#039;Theorem 2.&#039;&#039;&#039; The following row/column operations can be applied to a matrix &amp;lt;math&amp;gt;A&amp;lt;/math&amp;gt; by multiplying it on the left/right (respectively) by certain &#039;&#039;invertible&#039;&#039; &amp;quot;elementary matrices&amp;quot;:&lt;br /&gt;
# Swap two rows/columns&lt;br /&gt;
# Multiply a row/column by a nonzero scalar.&lt;br /&gt;
# Add a multiple of one row/column to another row/column.&lt;br /&gt;
|&amp;amp;nbsp;&amp;amp;nbsp;&amp;amp;nbsp;&lt;br /&gt;
|&#039;&#039;&#039;Proof.&#039;&#039;&#039; Semi-owed.&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;Solution of the problem.&#039;&#039;&#039; using these (invertible!) row/column operations we aim to bring &amp;lt;math&amp;gt;A&amp;lt;/math&amp;gt; to look as close as possible to an identity matrix, hoping it will be easy to determine the rank of the matrix we get at the end:&lt;br /&gt;
&lt;br /&gt;
{| border=&amp;quot;1px&amp;quot; cellspadding=&amp;quot;5&amp;quot; cellspacing=0 style=&amp;quot;font-size:90%;&amp;quot;&lt;br /&gt;
|+&lt;br /&gt;
|align=center|&#039;&#039;&#039;Do&#039;&#039;&#039;&lt;br /&gt;
|align=center|&#039;&#039;&#039;Get&#039;&#039;&#039;&lt;br /&gt;
|align=center|&#039;&#039;&#039;Do&#039;&#039;&#039;&lt;br /&gt;
|align=center|&#039;&#039;&#039;Get&#039;&#039;&#039;&lt;br /&gt;
|- valign=top &lt;br /&gt;
|1. Bring a &amp;lt;math&amp;gt;1&amp;lt;/math&amp;gt; to the upper left corner by swapping the first two rows and multiplying the first row (after the swap) by &amp;lt;math&amp;gt;1/4&amp;lt;/math&amp;gt;.&lt;br /&gt;
|align=center|&amp;lt;math&amp;gt;\begin{pmatrix}1&amp;amp;1&amp;amp;1&amp;amp;2&amp;amp;0\\0&amp;amp;2&amp;amp;4&amp;amp;2&amp;amp;2\\8&amp;amp;2&amp;amp;0&amp;amp;10&amp;amp;2\\6&amp;amp;3&amp;amp;2&amp;amp;9&amp;amp;1\end{pmatrix}&amp;lt;/math&amp;gt;&lt;br /&gt;
|2. Add &amp;lt;math&amp;gt;(-8)&amp;lt;/math&amp;gt; times the first row to the third row, in order to cancel the &amp;lt;math&amp;gt;8&amp;lt;/math&amp;gt; in position 3-1.&lt;br /&gt;
|align=center|&amp;lt;math&amp;gt;\begin{pmatrix}1&amp;amp;1&amp;amp;1&amp;amp;2&amp;amp;0\\0&amp;amp;2&amp;amp;4&amp;amp;2&amp;amp;2\\0&amp;amp;-6&amp;amp;-8&amp;amp;-6&amp;amp;2\\6&amp;amp;3&amp;amp;2&amp;amp;9&amp;amp;1\end{pmatrix}&amp;lt;/math&amp;gt;&lt;br /&gt;
|- valign=top&lt;br /&gt;
|3. Likewise add &amp;lt;math&amp;gt;(-6)&amp;lt;/math&amp;gt; times the first row to the fourth row, in order to cancel the &amp;lt;math&amp;gt;6&amp;lt;/math&amp;gt; in position 4-1.&lt;br /&gt;
|align=center|&amp;lt;math&amp;gt;\begin{pmatrix}1&amp;amp;1&amp;amp;1&amp;amp;2&amp;amp;0\\0&amp;amp;2&amp;amp;4&amp;amp;2&amp;amp;2\\0&amp;amp;-6&amp;amp;-8&amp;amp;-6&amp;amp;2\\0&amp;amp;-3&amp;amp;-4&amp;amp;-3&amp;amp;1\end{pmatrix}&amp;lt;/math&amp;gt;&lt;br /&gt;
|4. With similar column operations (you need three of those) cancel all the entries in the first row (except, of course, the first, which is used in the canceling).&lt;br /&gt;
|align=center|&amp;lt;math&amp;gt;\begin{pmatrix}1&amp;amp;0&amp;amp;0&amp;amp;0&amp;amp;0\\0&amp;amp;2&amp;amp;4&amp;amp;2&amp;amp;2\\0&amp;amp;-6&amp;amp;-8&amp;amp;-6&amp;amp;2\\0&amp;amp;-3&amp;amp;-4&amp;amp;-3&amp;amp;1\end{pmatrix}&amp;lt;/math&amp;gt;&lt;br /&gt;
|- valign=top&lt;br /&gt;
|5. Turn the 2-2 entry to a &amp;lt;math&amp;gt;1&amp;lt;/math&amp;gt; by multiplying the second row by &amp;lt;math&amp;gt;1/2&amp;lt;/math&amp;gt;.&lt;br /&gt;
|align=center|&amp;lt;math&amp;gt;\begin{pmatrix}1&amp;amp;0&amp;amp;0&amp;amp;0&amp;amp;0\\0&amp;amp;1&amp;amp;2&amp;amp;1&amp;amp;1\\0&amp;amp;-6&amp;amp;-8&amp;amp;-6&amp;amp;2\\0&amp;amp;-3&amp;amp;-4&amp;amp;-3&amp;amp;1\end{pmatrix}&amp;lt;/math&amp;gt;&lt;br /&gt;
|6. Using two row operations &amp;quot;clean&amp;quot; the second column; that is, cancel all entries in it other than the &amp;quot;pivot&amp;quot; &amp;lt;math&amp;gt;1&amp;lt;/math&amp;gt; at position 2-2.&lt;br /&gt;
|align=center|&amp;lt;math&amp;gt;\begin{pmatrix}1&amp;amp;0&amp;amp;0&amp;amp;0&amp;amp;0\\0&amp;amp;1&amp;amp;2&amp;amp;1&amp;amp;1\\0&amp;amp;0&amp;amp;4&amp;amp;0&amp;amp;8\\0&amp;amp;0&amp;amp;2&amp;amp;0&amp;amp;4\end{pmatrix}&amp;lt;/math&amp;gt;&lt;br /&gt;
|- valign=top&lt;br /&gt;
|7. Using three column operations clean the second row except the pivot.&lt;br /&gt;
|align=center|&amp;lt;math&amp;gt;\begin{pmatrix}1&amp;amp;0&amp;amp;0&amp;amp;0&amp;amp;0\\0&amp;amp;1&amp;amp;0&amp;amp;0&amp;amp;0\\0&amp;amp;0&amp;amp;4&amp;amp;0&amp;amp;8\\0&amp;amp;0&amp;amp;2&amp;amp;0&amp;amp;4\end{pmatrix}&amp;lt;/math&amp;gt;&lt;br /&gt;
|8. Clean up the row and the column of the &amp;lt;math&amp;gt;4&amp;lt;/math&amp;gt; in position 3-3 by first multiplying the third row by &amp;lt;math&amp;gt;1/4&amp;lt;/math&amp;gt; and then performing the appropriate row and column transformations. Notice that by pure luck, the &amp;lt;math&amp;gt;4&amp;lt;/math&amp;gt; at position 4-5 of the matrix gets killed in action.&lt;br /&gt;
|align=center|&amp;lt;math&amp;gt;\begin{pmatrix}1&amp;amp;0&amp;amp;0&amp;amp;0&amp;amp;0\\0&amp;amp;1&amp;amp;0&amp;amp;0&amp;amp;0\\0&amp;amp;0&amp;amp;1&amp;amp;0&amp;amp;0\\0&amp;amp;0&amp;amp;0&amp;amp;0&amp;amp;0\end{pmatrix}&amp;lt;/math&amp;gt;&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
But the matrix we now have represents a linear transformation &amp;lt;math&amp;gt;S&amp;lt;/math&amp;gt; satisfying &amp;lt;math&amp;gt;S(v_1,\,v_2,\,v_3,\,v_4\,v_5)=(w_1,\,w_2,\,w_3,\,0,\,0)&amp;lt;/math&amp;gt; for some bases &amp;lt;math&amp;gt;(v_i)_{i=1}^5&amp;lt;/math&amp;gt; of &amp;lt;math&amp;gt;V&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;(w_j)_{j=1}^4&amp;lt;/math&amp;gt; of &amp;lt;math&amp;gt;W&amp;lt;/math&amp;gt;. Thus the image (range) of &amp;lt;math&amp;gt;S&amp;lt;/math&amp;gt; is spanned by &amp;lt;math&amp;gt;\{w_1,w_2,w_3\}&amp;lt;/math&amp;gt;, and as these are independent, they form a basis of the image. Thus the rank of &amp;lt;math&amp;gt;S&amp;lt;/math&amp;gt; is &amp;lt;math&amp;gt;3&amp;lt;/math&amp;gt;. Going backward through the &amp;quot;matrix reduction&amp;quot; process above and repeatedly using theorems 1 and 2, we find that the rank of &amp;lt;math&amp;gt;T&amp;lt;/math&amp;gt; must also be &amp;lt;math&amp;gt;3&amp;lt;/math&amp;gt;.&lt;/div&gt;</summary>
		<author><name>Psp</name></author>
	</entry>
	<entry>
		<id>https://drorbn.net/index.php?title=06-240/Class_Photo&amp;diff=2275</id>
		<title>06-240/Class Photo</title>
		<link rel="alternate" type="text/html" href="https://drorbn.net/index.php?title=06-240/Class_Photo&amp;diff=2275"/>
		<updated>2006-10-07T20:55:06Z</updated>

		<summary type="html">&lt;p&gt;Psp: Added Philip&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;Our class on September 28, 2006:&lt;br /&gt;
&lt;br /&gt;
[[Image:06-240-ClassPhoto.jpg|thumb|centre|500px|Class Photo: click to enlarge]]&lt;br /&gt;
{{06-240/Navigation}}&lt;br /&gt;
&lt;br /&gt;
Please identify yourself in this photo! There are two ways to do that:&lt;br /&gt;
&lt;br /&gt;
* [[Special:Userlogin|Log in]] to this Wiki and edit this page. Put your name, userid, email address and location in the picture in the alphabetical list below.&lt;br /&gt;
* Send [[User:Drorbn|Dror]] an email message with this information.&lt;br /&gt;
&lt;br /&gt;
The first option is more fun but less private.&lt;br /&gt;
&lt;br /&gt;
===Who We Are...===&lt;br /&gt;
&lt;br /&gt;
{| align=center border=1 &lt;br /&gt;
|-&lt;br /&gt;
!First name&lt;br /&gt;
!Last name&lt;br /&gt;
!UserID&lt;br /&gt;
!Email&lt;br /&gt;
!In the photo&lt;br /&gt;
!Comments&lt;br /&gt;
{{Photo Entry|last=Bar-Natan|first=Dror|userid=Drorbn|email=drorbn@ math.toronto.edu|location=facing everybody, as the photographer|comments=Take this entry as a model and leave it first. Otherwise alphabetize by last name. Feel free to leave some fields blank}}&lt;br /&gt;
{{Photo Entry|last=Beach|first=Laura|userid=Beacher|email=laura.beach@ utoronto.ca|location=3rd row from front, far right in light shirt, in front of guy in hat.|comments=Lookin&#039; good, everybody!}}&lt;br /&gt;
{{Photo Entry|last=Bumagin|first=Mark|userid=Bumaginm|email=mark.bumagin@ utoronto.ca|location=Guy in light blue collar shirt, second row, third on the right|comments= }}&lt;br /&gt;
{{Photo Entry|last=Carberry|first=Mick|userid=MC|email=Mick.Carberry@ utoronto.ca|location=long haired, bearded old guy in back|comments= }}&lt;br /&gt;
{{Photo Entry|last=Cerezo|first=Richard|userid=Cerezo|email=richard.cerezo@ utoronto.ca|location=Guy in black jacket and black hat on far right, second from the bottom. |comments= }}&lt;br /&gt;
{{Photo Entry|last=Dong|first=Qi (Tom)|userid=houseofglass|email=tom_dongqi@ hotmail.com|location= The only chinese blonde guy with glasses located on the second row in the main picture|comments=testing 1 2 3 4 5 6 7 8 9 }}&lt;br /&gt;
{{Photo Entry|last=Dzamba|first=Michael|userid=dzambami|email=michael.dzamba@ utoronto.ca|location=In the middle, sort of, have a bit of extra hair on my head, forms sort of a spherical volume, sometimes visible from a distance|comments=&amp;quot;The obvious mathematical breakthrough would be development of an easy way to factor large prime numbers.&amp;quot; - Bill Gates , The Road Ahead (his book), P265, This is not a typo on my behalf ;) }}&lt;br /&gt;
{{Photo Entry|last=Gokmen|first=Murat|userid=Gokmen|email=uoftmurat@ gmail.com|location=the guy second row @second from the right:with the shining jacket &amp;amp; blue hat|comments=}}&lt;br /&gt;
{{Photo Entry|last=Halacheva|first=Iva|userid=Haliv|email=iva.halacheva@ utoronto.ca|location=Third row from the front, light brown jacket|comments= }}&lt;br /&gt;
{{Photo Entry|last=Kaifosh|first=Patrick|userid=Pat|email=patrick.kaifosh@ utoronto.ca|location=Front row, rightmost.|comments= }}&lt;br /&gt;
{{Photo Entry|last=Koziar|first=John|userid=John.koziar|email=|location=Front row, centre.|comments= }}&lt;br /&gt;
{{Photo Entry|last=McIntyre|first=Sean|userid=Smcintyre|email=s.mcintyre@ utoronto.ca|location=mini-picture, fourth from the right|comments= }}&lt;br /&gt;
{{Photo Entry|last=Ng|first=Gilbert|userid=Gilbert|email=gilbert.ng@ utoronto.ca|location=to the right of the pole in the back, last row|comments= }}&lt;br /&gt;
{{Photo Entry|last=Park|first=Philip|userid=Psp|email=philip.park@utoronto.ca|location=2nd row from the back, 3rd from the right, wearing a light-blue shirt with a dark-blue jacket|comments=}}&lt;br /&gt;
{{Photo Entry|last=Qiao|first=Li|userid=joy9999|email=li.qiao@ utoronto.ca|location=behind the guy in black, last row|comments= }}&lt;br /&gt;
{{Photo Entry|last=Soreanu|first=Alla|userid=Alla|email=alla.soreanu@ utoronto.ca|location=mini-picture, first from the left|comments= }}&lt;br /&gt;
{{Photo Entry|last=SUN|first=LUYANG|userid=Luyang|email=luyang.sun@ utoronto.ca|location=the guy in the middle, wearing a white coat row3 col4|comments=Hello World}}&lt;br /&gt;
{{Photo Entry|last=Tai|first=Johnathan|userid=Zapyre|email=zapyre_1@ hotmail.com|location= At the very back, left hand corner (all blue) |comments= &amp;gt;.&amp;lt;}}&lt;br /&gt;
{{Photo Entry|last=Veytsman|first=Maxim|userid=Mveytsman|email=|location=small picture in the bottom left corner.  Second one from the right.|comments=}}&lt;br /&gt;
{{Photo Entry|last=Wong|first=Pak|userid=wongpak|email=plwong@ utoronto.ca|location=Third row from the back, left most, black shirt|comments= }}&lt;br /&gt;
{{Photo Entry|last=Kim|first=Taehyung|userid=Taehyung Kim|email=taehyung.Kim@utoronto.ca|location= Asian,Second row from the back, Second right most, black shirt,black backpack|comments=  }}&lt;br /&gt;
{{Photo Entry|last=Matskin|first=Jeffrey|userid=jeff.matskin|email=jeff.matskin@utoronto.ca|location= Bottom right corner of people, farthest to the right, white shirt|comments=  }}&lt;/div&gt;</summary>
		<author><name>Psp</name></author>
	</entry>
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