<?xml version="1.0"?>
<feed xmlns="http://www.w3.org/2005/Atom" xml:lang="en">
	<id>https://drorbn.net/api.php?action=feedcontributions&amp;feedformat=atom&amp;user=70.49.220.158</id>
	<title>Drorbn - User contributions [en]</title>
	<link rel="self" type="application/atom+xml" href="https://drorbn.net/api.php?action=feedcontributions&amp;feedformat=atom&amp;user=70.49.220.158"/>
	<link rel="alternate" type="text/html" href="https://drorbn.net/index.php?title=Special:Contributions/70.49.220.158"/>
	<updated>2026-06-16T09:12:09Z</updated>
	<subtitle>User contributions</subtitle>
	<generator>MediaWiki 1.39.6</generator>
	<entry>
		<id>https://drorbn.net/index.php?title=06-240/Classnotes_For_Tuesday_October_10&amp;diff=2426</id>
		<title>06-240/Classnotes For Tuesday October 10</title>
		<link rel="alternate" type="text/html" href="https://drorbn.net/index.php?title=06-240/Classnotes_For_Tuesday_October_10&amp;diff=2426"/>
		<updated>2006-10-22T08:28:09Z</updated>

		<summary type="html">&lt;p&gt;70.49.220.158: /* A Quick Summary by {{Dror}} */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;{{06-240/Navigation}}&lt;br /&gt;
&lt;br /&gt;
====Scan of Lecture Notes====&lt;br /&gt;
&lt;br /&gt;
* PDF file by [[User:Alla]]: [[Media:MAT_Lect009.pdf|Week 5 Lecture 1 notes]]&lt;br /&gt;
&lt;br /&gt;
==A Quick Summary by {{Dror}}==&lt;br /&gt;
(Intentionally terse. A sea of details appears in the book and already appeared on the blackboard. But these are useless without some &#039;&#039;&#039;organizing principles&#039;&#039;&#039;; in some sense, &amp;quot;understanding&amp;quot; is precisely being able to see those principles within the sea of details. Yet don&#039;t fool yourself into thinking that the principles are enough even without the details!)&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;Theorem.&#039;&#039;&#039; A finite generating set &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt; has a subset which is a basis.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;Proof Sketch.&#039;&#039;&#039; Grab more and more elements of &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt; so long as they are linearly independent. When you can&#039;t any more, you have a basis.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;Lemma.&#039;&#039;&#039; (The Replacement Lemma) If &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt; generates and &amp;lt;math&amp;gt;L&amp;lt;/math&amp;gt; is linearly independent, then &amp;lt;math&amp;gt;|L|\leq|G|&amp;lt;/math&amp;gt; and you can replace &amp;lt;math&amp;gt;|L|&amp;lt;/math&amp;gt; of the elements of &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt; by the elements of &amp;lt;math&amp;gt;L&amp;lt;/math&amp;gt;, and still have a generating set.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;Proof Sketch.&#039;&#039;&#039; Insert the elements of &amp;lt;math&amp;gt;L&amp;lt;/math&amp;gt; one by one, and for each one that comes in, take one out of &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt;. Which one? One used in expressing the newcomer in terms of the vectors already in the set.  Such one must exist or else the newcomer is a linear combination of some of the elements of &amp;lt;math&amp;gt;L&amp;lt;/math&amp;gt;, but &amp;lt;math&amp;gt;L&amp;lt;/math&amp;gt; is linearly independent.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;Theorem.&#039;&#039;&#039; If a vector space &amp;lt;math&amp;gt;V&amp;lt;/math&amp;gt; has a finite basis, all bases thereof are finite and have the same number of elements, the &amp;quot;dimension of &amp;lt;math&amp;gt;V&amp;lt;/math&amp;gt;&amp;quot;.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;Proof Sketch.&#039;&#039;&#039; By replacement, &amp;lt;math&amp;gt;|\alpha|\leq|\beta|&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;|\beta|\leq|\alpha|&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;Theorem.&#039;&#039;&#039; Assume &amp;lt;math&amp;gt;\dim V=n&amp;lt;/math&amp;gt;.&lt;br /&gt;
# If &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt; generates, &amp;lt;math&amp;gt;|G|\geq n&amp;lt;/math&amp;gt;. In case of equality, &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt; is a basis.&lt;br /&gt;
# If &amp;lt;math&amp;gt;L&amp;lt;/math&amp;gt; is linearly independent, &amp;lt;math&amp;gt;|L|\leq n&amp;lt;/math&amp;gt;. In case of equality, &amp;lt;math&amp;gt;L&amp;lt;/math&amp;gt; is a basis.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;Proof Sketch.&#039;&#039;&#039;&lt;br /&gt;
# Find a basis within &amp;lt;math&amp;gt;G&amp;lt;/math&amp;gt;; it has &amp;lt;math&amp;gt;n&amp;lt;/math&amp;gt; elements.&lt;br /&gt;
# Use replacement to place the elements of &amp;lt;math&amp;gt;L&amp;lt;/math&amp;gt; within some basis.&lt;/div&gt;</summary>
		<author><name>70.49.220.158</name></author>
	</entry>
</feed>