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\newlabel{eq:ATPhiandV}{{19}{55}{The relationship between $\sKTG $ and $\wTF $}{equation.4.19}{}}
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\newlabel{fig:NooseCappedProof}{{26}{56}{The proof of Equation (\ref {eq:NooseCapped}). Note that the unzips are ``illegal'', as the strand directions don't match. This can be fixed by inserting a small bubble at the bottom of the noose and doing a number of orientation switches. As this doesn't change the result or the main argument, we suppress the issue for simplicity. Equation (\ref {eq:NooseCapped}) is obtained from this result by multiplying by $S(C)^{-1}$ on the bottom and by $C^{-1}$ on the top}{figure.26}{}}
\newlabel{eq:NooseSymmetry}{{20}{56}{The relationship between $\sKTG $ and $\wTF $}{equation.4.20}{}}
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\@writefile{lof}{\contentsline {figure}{\numberline {27}{\ignorespaces  The J-K flip flop, a very basic memory cell, is an electronic circuit that can be realized using 9 components --- two triple-input ``and'' gates, two standard ``nor'' gates, and 5 ``junctions'' in which 3 wires connect (many engineers would not consider the junctions to be real components, but we do). Note that the ``crossing'' in the middle of the figure is merely a projection artifact and does not indicate an electrical connection, and that electronically speaking, we need not specify how this crossing may be implemented in ${\mathbb  R}^3$. The J-K flip flop has 5 external connections (labelled J, K, CP, Q, and Q') and hence in the circuit algebra of computer parts, it lives in $C_5$. In the directed circuit algebra of computer parts it would be in $C_{3,2}$ as it has 3 incoming wires (J, CP, and K) and two outgoing wires (Q and Q'). }}{57}{figure.27}\protected@file@percent }
\newlabel{fig:FlipFlop}{{27}{57}{The J-K flip flop, a very basic memory cell, is an electronic circuit that can be realized using 9 components --- two triple-input ``and'' gates, two standard ``nor'' gates, and 5 ``junctions'' in which 3 wires connect (many engineers would not consider the junctions to be real components, but we do). Note that the ``crossing'' in the middle of the figure is merely a projection artifact and does not indicate an electrical connection, and that electronically speaking, we need not specify how this crossing may be implemented in $\bbR ^3$. The J-K flip flop has 5 external connections (labelled J, K, CP, Q, and Q') and hence in the circuit algebra of computer parts, it lives in $C_5$. In the directed circuit algebra of computer parts it would be in $C_{3,2}$ as it has 3 incoming wires (J, CP, and K) and two outgoing wires (Q and Q')}{figure.27}{}}
\@writefile{lof}{\contentsline {figure}{\numberline {28}{\ignorespaces  The circuit algebra product of 4 big black components and 1 small black component carried out using a green wiring diagram, is an even bigger component that has many golden connections (at bottom). When plugged into a yet bigger circuit, the CPU board of a laptop, our circuit functions as 4,294,967,296 binary memory cells. }}{58}{figure.28}\protected@file@percent }
\newlabel{fig:Circuit}{{28}{58}{The circuit algebra product of 4 big black components and 1 small black component carried out using a green wiring diagram, is an even bigger component that has many golden connections (at bottom). When plugged into a yet bigger circuit, the CPU board of a laptop, our circuit functions as 4,294,967,296 binary memory cells}{figure.28}{}}
\newlabel{subsec:sKTGgensProof}{{5.2}{58}{Proof of Proposition \ref {prop:sKTGgens}}{subsection.5.2}{}}
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\bibcite{CarterSaito:KnottedSurfaces}{CS}
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\bibcite{Kuperberg:VirtualLink}{Kup}
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\bibcite{Loday:LeibnizAlg}{Lod}
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\bibcite{MurakamiOhtsuki:KTGs}{MO}
\bibcite{Satoh:RibbonTorusKnots}{Sa}
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