User:Drorbn/06-1350-HW4: Difference between revisions

Revision as of 16:27, 18 November 2006

Our generators are $T$ , $R$ , $Y=\Phi$ and $B^{\pm }$ (we might consider splitting $Y$ into two, $Y^{up}$ and $Y^{dn}$ ):

The picture is

In formulas, this is

(1230)^{\star }B^{+}(1213)^{\star }B^{+}(1023)^{\star }B^{+}=(1123)^{\star }B^{+}(1203)^{\star }B^{+}(1231)^{\star }B^{+}

.

Thus the R3 component of $d$ is

(1230)^{\star }b^{+}+(1213)^{\star }b^{+}+(1023)^{\star }b^{+}-(1123)^{\star }b^{+}-(1203)^{\star }b^{+}-(1231)^{\star }b^{+}

.

@@ Line 1: / Line 1: @@
 ===The Generators===
-Our generators are <math>T</math>, <math>R</math>, <math>Y=\Phi</math> and <math>B^{\pm}</math>. (You might consider splitting <math>Y</math> into two, <math>Y^{up}</math> and <math>Y^{dn}</math>). In pictures, they are
+Our generators are <math>T</math>, <math>R</math>, <math>Y=\Phi</math> and <math>B^{\pm}</math> (we might consider splitting <math>Y</math> into two, <math>Y^{up}</math> and <math>Y^{dn}</math>):
 {| align=center
-|- align=center
+|- align=center valign=middle
+|align=left|Picture
 |
 |
@@ Line 10: / Line 11: @@
 |[[Image:06-1350-BPlus.svg|100px]]
 |
-|- align=center
+|- align=center valign=middle
+|align=left|Generator
 |<math>T</math>
 |<math>R</math>
@@ Line 17: / Line 19: @@
 |<math>B^+</math>
 |<math>B^-</math>
+|- align=center valign=middle
+|align=left|Perturbation
+|<math>t</math>
+|<math>r</math>
+|<math>y^u</math>
+|<math>y^d</math>
+|<math>b^+</math>
+|<math>b^-</math>
 |}