The Envelope of The Alexander Polynomial

From Drorbn
Revision as of 09:13, 1 May 2007 by Drorbn (Talk | contribs)

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
Jump to: navigation, search
In Preparation

The information below is preliminary and cannot be trusted! (v)


The Internal Kernel of the Alexander Polynomial

All that there is here comes from 06-1350/Class Notes for Tuesday October 24. Many further relevant facts are in arXiv:q-alg/9602014 by José M. Figueroa-O'Farrill, Takashi Kimura, Arkady Vaintrob and in arXiv:math.QA/0204346 by Jens Lieberum.

At the moment I know of just three relations in the internal kernel of the Alexander polynomial: the bubble relation, the H relation and the 4Y relation:

The Bubble Relation
The H Relation
The 4Y Relation

I have good reasons to suspect that there are further relations. But at the moment I don't know what they are, so below we will make do with what we have.

The VS-Algebra Envelope of the Alexander Polynomial

Alexander-Conway, Precisely

Let C(z) denote the Conway polynomial and A(t) denote the Alexander polynomial. By [Bar-Natan_Garoufalidis_96] we know that

\frac{\hbar}{e^{\hbar/2}-e^{-\hbar/2}}C(e^{\hbar/2}-e^{-\hbar/2}) = \frac{\hbar}{e^{\hbar/2}-e^{-\hbar/2}}A(e^\hbar)

is a canonical Vassiliev power series. Let d denote "half a bubble". The following theorem follows easily from the above canonicity statement and the fact that W_C(d^{2n})=(-2\hbar^2)^n (in shorter and less precise form, \hbar=W_C(id/\sqrt2)), where W_C is the weight system of the Alexander-Conway polynomial:

Theorem. Let K be a knot and let Z(K) be the Kontsevich integral of K. Then within the envelope of the Alexander-Conway polynomial,

Z(K) = \frac{id/\sqrt2}{e^{id/2\sqrt2}-e^{-id/2\sqrt2}} C(e^{id/2\sqrt2}-e^{-id/2\sqrt2}) = \frac{id/\sqrt2}{e^{id/2\sqrt2}-e^{-id/2\sqrt2}} A(e^{id/\sqrt2}).


[Bar-Natan_Garoufalidis_96] ^  Dror Bar-Natan and Stavros Garoufalidis, On the Melvin-Morton-Rozansky Conjecture, Inventiones Mathematicae 125 (1996) 103-133.