Notes for AKT-140228/0:41:45: Difference between revisions

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(Created page with "'''<math>(A^g)^h = A^{(gh)}</math> ?''' <center><math>\begin{align} (A^g)^h &= h^{-1}(g^{-1}Ag + g^{-1}\mathrm{d}g)h + h^{-1}\mathrm{d}h \\ &= \end{align} </math></center>")
 
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<center><math>\begin{align}
<center><math>\begin{align}
(A^g)^h &= h^{-1}(g^{-1}Ag + g^{-1}\mathrm{d}g)h + h^{-1}\mathrm{d}h \\
(A^g)^h &= h^{-1}(g^{-1}Ag + g^{-1}\mathrm{d}g)h + h^{-1}\mathrm{d}h \\
&= (gh)^{-1}A(gh) + (gh)^{-1}\mathrm{d}(gh) + h^{-1}\mathrm{d}h\\
&=
&= A^{(gh)} + h^{-1}\mathrm{d}h
\end{align}
\end{align}
</math></center>
</math></center>

Revision as of 15:11, 18 July 2018

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