Notes for AKT-140207/0:42:32: Difference between revisions
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Leo algknt (talk | contribs) (Created page with "'''Showing <math>\Psi(A) = A\wedge \mathrm{d}A</math> is invariant under <math>A\mapsto A + \mathrm{d}f</math>''' <center><math>\begin{align} \Psi(A + \mathrm{d}f) &= (A + \ma...") |
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'''Showing <math>\Psi(A) = A\wedge \mathrm{d}A</math> is invariant under <math>A\mapsto A + \mathrm{d}f</math>''' |
'''Showing <math>\Psi(A) = A\wedge \mathrm{d}A</math> is invariant under <math>A\mapsto A + \mathrm{d}f</math>''' |
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<center><math>\begin{align} |
<center><math>\begin{align} |
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\Psi(A + \mathrm{d}f) &= (A + \mathrm{d}f)\wedge d(A + \mathrm{d}f)\\ |
\Psi(A + \mathrm{d}f) &= (A + \mathrm{d}f)\wedge \mathrm{d}(A + \mathrm{d}f)\\ |
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&= (A + \mathrm{d}A)\wedge \mathrm{d}A,\;\;\;\;\; \mathrm{since \; d\circ d = 0}\\ |
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&= |
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&= A\wedge \mathrm{d}A. |
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\end{align}</math> </center> |
\end{align}</math> </center> |
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Latest revision as of 14:51, 18 July 2018
Showing is invariant under
