Notes for AKT-091008-1/0:51:07: Difference between revisions

Latest revision as of 06:40, 8 November 2011

Given a planar diagram, number of 3-colorings of the edges = number of 4-colorings of the regions in the plane divided by the diagram.

Bijection using the Klein 4 group as colors and add when crossing edges.

Revision as of 01:56, 14 October 2009 (view source) Conan777 (talk \| contribs) No edit summary		Latest revision as of 06:40, 8 November 2011 (view source) Iva (talk \| contribs) No edit summary
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	Given ~~planer~~ diagram, number of 3-colorings of the edges = number of 4-colorings of the plane divided by the diagram.		Given a planar diagram, number of 3-colorings of the edges = number of 4-colorings of the regions in the plane divided by the diagram.

	Bijection using the Klein 4 group as colors and add when crossing edges.		Bijection using the Klein 4 group as colors and add when crossing edges.