Notes for AKT-090917-1/0:46:11

Let $K$ be a knot, $J_{K}(q)$ be its Jones polynomial. Substitute $q=e^{x}$ and expand $J_{k}(e^{x})$ into power series. We have $J_{K}(e^{x})=\sum _{n}j_{(n,K)}\ x^{n}$ where the coefficients $j_{(n,\cdot )}:\{knots\}\rightarrow \mathbb {Z}$ are knot invariants.

Thm: $j_{(n,\cdot )}$ is of type $n$.