06-240/Classnotes For Thursday, September 28: Difference between revisions

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''Example''
To be continued ...
1. Let P<sub>3</sub>(<math>\Re</math>)={ax<sup>3</sup>+bx<sup>2</sup>+cx+d}<math>\subseteq</math>P(<math>\Re</math>), ''a'', ''b'', ''c'', ''d'', <math>\in \Re</math>.
''u''<sub>1</sub>=''x''<sup>3</sup>-2''x''<sup>2</sup>-5''x''-3
''u''<sub>2</sub>=3''x''<sup>3</sup>-5''x''<sup>2</sup>-4''x''-9
''v''=2''x''<sup>3</sup>-2''x''<sup>2</sup>+12''x''-6

Revision as of 16:25, 29 September 2006

Linear Combination

Definition: Let (ui) = (u1, u2, ..., un) be a sequence of vectors in V. A sum of the form

ai F, aiui = a1u1 + a2u2+ ... +anun

is called a "Linear Combination" of the ui.

Span

span(ui):= The set of all possible linear combinations of the ui's.


If V is any subset,

span := The set of all linear combination of vectors in
=

even if is empty.

Theorem: For any V, span is a subspace of V.

Proof:
1. 0 span .
2. Let x span , Let x span , x = aiui, ui , y = bivi, vi . x+y = aiui + bivi = ciwi where ci=(a1, a2,...,an, b1, b2,...,bm) and wi=ci=(u1, u2,...,un, v1, v2,...,vm).
3. cx= c aiui= (cai)ui span .


Example 1. Let P3()={ax3+bx2+cx+d}P(), a, b, c, d, . u1=x3-2x2-5x-3 u2=3x3-5x2-4x-9 v=2x3-2x2+12x-6